Question

Dado um paralelepipedo retangulo de dimensoes 2m 3m e 6m calcule a diagonal

Answer 1

Boa tarde!

$d= \sqrt{2^2+3^2+6^2} \\ d= \sqrt{4+9+36} \\ d= \sqrt{49} \\ d= 7 m$

Bons estudos!

Answer 2

D² = a² + b² + c² ---> D = $\sqrt{a^2+b^2+c^2}$

D² = 2² + 3² + 6²
$D= \sqrt{2^2+3^2+6^2}$

$D= \sqrt{4+9+36}--> D= \sqrt{49}--> D=7$m