Question

dado sen x=3/5 determine a tg x, sabendo que 0<x x/2

Answer 1

Sen^2 x+cos^2 x=1
(3/5)^2+cos^2 x=1
cos^2 x=1-9/25
cos^2 x=16/25
cos x=4/5

tgx = senx/cosx
tgx=(3/5)(4/5)
tgx=15/20