Question

Dado sem x = 1/5 e Cos x √2/5 , determine tg x.​

Answer 1

Resposta:

Tgx=√2/2

Explicação passo-a-passo:

Dado sem x = 1/5 e Cos x √2/5 , determine tg x.

Tgx = senx /cosx

Tgx=(1/5)/(√2/5)

Tgx=5/5√2

Tgx=1/√2 ( racionalizando)

Tgx= (1/√2).(√2/√2)

Tgx=√2/2

Answer 2

$tgx = \sqrt[2]{2} / 2$

Para calcular o valor da tangente, basta dividir o seno pelo cosseno.

$tgx = senx / cosx\\\\tgx = 1/5 : \sqrt[2]{2}/5\\\\tgx = (1/5). (5 / \sqrt[2]{2}\\\\tgx = 5 / 5.\sqrt[2]{2} \\\\tgx = 1 / \sqrt[2]{2}\\\\tgx = 1.\sqrt[2]{2} / \sqrt[2]{2}.\sqrt[2]{2} \\\\tgx = \sqrt[2]{2} / 2$

Veja mais em:

https://brainly.com.br/tarefa/23622167

https://brainly.com.br/tarefa/49045642