Question

dado que log 5=m ,calcular A= log75+log2/3

Answer 1

log 75 = log (5.5.3) = log 5+ log 5+ log 3
log 2/3 = log 2 - log 3
log 2= log 10/5 = log 10 - log 5
log 10=1
A = log 5 + log 5 + log 3 + log 2 - log 3 (cancela log 3 com log 3)
A = m + m + log 2
A= 2m + log 10 - log 5
A= 2m + 1 - m
A= m+1