Question

Dado o triângulo retângulo abaixo, calcule:
a)sen0=
b)cos0=
c)tg0=​

Answer 1

a)sen0= co/hip = 2/2√5 =

1/√5 *(√5/√5)=√5 /5

b)cos0= ca/hip = 4/2√5=

2/√5 *(√5/√5)=2√5 /5

c)tg0= co/ca = 2/4 = 1/2

Answer 2

Explicação passo-a-passo:

a)

$\sf sen~\theta=\dfrac{cateto~oposto}{hipotenusa}$

$\sf sen~\theta=\dfrac{2}{2\sqrt{5}}$

$\sf sen~\theta=\dfrac{1}{\sqrt{5}}$

$\sf sen~\theta=\dfrac{1}{\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}}$

$\sf \red{sen~\theta=\dfrac{\sqrt{5}}{5}}$

b)

$\sf cos~\theta=\dfrac{cateto~adjacente}{hipotenusa}$

$\sf cos~\theta=\dfrac{4}{2\sqrt{5}}$

$\sf cos~\theta=\dfrac{2}{\sqrt{5}}$

$\sf cos~\theta=\dfrac{2}{\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}}$

$\sf \red{cos~\theta=\dfrac{2\sqrt{5}}{5}}$

c)

$\sf tg~\theta=\dfrac{cateto~oposto}{cateto~adjacente}$

$\sf tg~\theta=\dfrac{2}{4}$

$\sf \red{tg~\theta=\dfrac{1}{2}}$