Question

dado o triângulo abaixo, calcule o valor de x que está faltando ​

Answer 1

Resposta:

A)$x^2=8^2+6^2\\x^2=64+36\\x^2=100\\x=\sqrt{100} \\x=10\\\\b) x^2=20^2+15^2\\x^2=400+225\\x^2=625\\x=\sqrt{625} \\x=25\\\\c) 5^2=x^2+4^2\\25=x^2+16\\-x^2=16-25\\-x^2=-9\\x^2=9\\x=\sqrt{9} \\x=3\\\\d)13^2=5^2+x^2\\169=25+x^2\\x^2=169-25\\x^2=144\\x=\sqrt{144} \\x=12$