Question

dado o ponto p(3,2),determine a distância r:x=-1​

Answer 1

Resposta:

a)

x =  -1

-1 - x = 0

\begin{gathered}D = \frac{|ax + by + c|}{\sqrt{a^2 + b^2}} \\ \\ D = \frac{|-1.3 + 0.2 - 1|}{\sqrt{1^2 + 0^2}} \\ \\ D = \frac{|-3 - 1|}{\sqrt{1}} \\ \\ D = \frac{|-4|}{1} \\ \\ D = 4\end{gathered}D=a2+b2∣ax+by+c∣D=12+02∣−1.3+0.2−1∣D=1∣−3−1∣D=1∣−4∣D=4

b)

 

y - 4 = 2/5(x - 3)

y - 4 - 2x/5 + 6/5 = 0 

5y - 20 + 2x + 6 = 0

5y - 2x -14 = 0 

\begin{gathered}D = \frac{|ax + by + c|}{\sqrt{a^2 + b^2}} \\ \\ D = \frac{|5.2 + (-2).3 -14|}{\sqrt{(-2)^2 + 5^2}} \\ \\ D = \frac{|10 - 6 - 14|}{\sqrt{4 + 25}} \\ \\ D = \frac{|10 - 20|}{\sqrt{29}} \\ \\ D = \frac{|-10|}{\sqrt{29}} \\ \\ D = \frac{10}{\sqrt{29}} = \frac{10 \sqrt{29}}{29}\end{gathered}D=a2+b2∣ax+by+c∣D=(−2)2+52∣5.2+(−2).3−14∣D=4+25∣10−6−14∣D=29∣10−20∣D=29∣−10∣D=2910=291029

Explicação passo-a-passo:

e bem difossiu mas