Question

Dado o polonio p(x)=4x⁴+3x³-2x²+x+k e sabendo que p(1)=2, entao o valor de p(3) vale:

Answer 1

$\begin{array}{l}p( 1) =4\cdotp 1^{4} +3\cdotp 1^{3} -2\cdotp 1^{2} +1+k=2\Longrightarrow \\\\\Longrightarrow 6+k=2\Longrightarrow k=-4\\\\\therefore p( 3) =4\cdotp 3^{4} +3\cdotp 3^{3} -2\cdotp 3^{2} +3-4=324+81-18-1\Longrightarrow \\\\\Longrightarrow \ \boxed{\boxed{p( 3) =386}}\end{array}$