Question

dado o número complexo z = 3√3 + 3i calcule z elevado a 4

Answer 1

z = 3√3 + 3i

z²=(3*9+ 18i√3+9i²) =27+18i√3-9 =18+18i√3=18*(1+i√3)

z⁴=18² * (1+i√3)²=324 *(1+2i√3-3)=324* (2i√3-2)=648*(-1+i√3 )