Question

Dado log a = 5 e log c = 2, calcule:
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Answer 1

Resposta:

log(a) = 5

log(c) = 2

a) log(a*c) = log(a) + log(c) = 5 + 2 = 7

b) log(a/c) = log(a) - log(c) = 5 - 2 = 3

c) log(a/c)-² = log(c²/a²) = 2log(c) - 2log(a) = 4 - 10 = -6