Question

Dado f(x) = (√2/2)2x e g(x) = 64x, determine para quais valores reais de x temos f(x) > g(x).

Answer 1

Caso tenha problemas para visualizar a resposta experimente abrir pelo navegador

https://brainly.com.br/tarefa/33911093?answering=true&answeringSource=feedPublic%2FhomePage%2F45

$\sf{f(x)=\left(\dfrac{\sqrt{2}}{\diagup\!\!\!2}\right)}\cdot\diagup\!\!\!2x=2\sqrt{2}x\\\sf g(x)=64x\\\sf f(x)>g(x)\\\sf 2\sqrt{2}x>64x\\\sf 2\sqrt{2}x-64x>0\\\sf{x\cdot(2\sqrt{2}-64)}>0\\\sf x>\dfrac{0}{2\sqrt{2}-64}\\\sf x>0$