Question

Dado f(3)=2 e f(-1)=5,em f(x)=ax +b,determine f(0)+f(1)​

Answer 1

Explicação passo-a-passo:

f(3)=2

f(-1)=5

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3a+b=2

-a+b= 5 . (3)

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3a+b=2

-3a+3b=15

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b+3b=15+2

4b= 17

b=17/4

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-a+b=5

-a=5-b

-a=5-17/4

-a=(20-17)/4

-a= 3/4

a= -3/4

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F(x)= ax+b

F(x)=-3/4x+17/4

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f(0)+f(1)=-3/4.(0)+17/4 +[ -3/4.(1)+17/4 ]

f(0)+f(1)=0+17/4 -3/4 +17/4

f(0)+f(1)=17/4+17/4-3/4

f(0)+f(1)=(17+17-3)/4

f(0)+f(1)=(34-3)/4

f(0)+f(1)=31/4