Question

dado cos a = raiz quadrada de 3/4 ache o seno do ângulo a

Answer 1

Cos a=√3/√4

Cos a =√12/4

a^2=b^2+c^2

4^2=x^2+√12^2

x^2=16-12

x=√4

x=2

Sen a =2/4

Sen a= 1/2