Matemática, perguntado por TiagoLeoni, 1 ano atrás

Dadas as matrizes ( podem me ajudar)

Anexos:

Soluções para a tarefa

Respondido por lavinnea
1
A+B+C=  \\  \\ $$\left(\begin{array}{cc}4&-3 \\ 6&2\end{array}\right)$$+$$\left(\begin{array}{cc}3&-4 \\ -2&6\end{array}\right)$$+$$\left(\begin{array}{cc}5&1 \\ 7&-2\end{array}\right)$$= \\  \\  \\ $$\left(\begin{array}{cc}4+3+5&-3-4+1 \\ 6-2+7&2+6-2\end{array}\right)$$= \\  \\  \\ $$\left(\begin{array}{cc}12&-6 \\ 11&6\end{array}\right)$$

C-A= \\  \\ $$\left(\begin{array}{cc}5-4&1+3 \\ 7-6&-2+2\end{array}\right)$$=$$\left(\begin{array}{cc}1&4 \\ 1&0\end{array}\right)$$


-8B= \\  \\ -8$$\left(\begin{array}{cc}3&2 \\ -2&6\end{array}\right)$$=$$\left(\begin{array}{cc}-8(3)&-8(-4) \\ -8(-2)&-8(6)\end{array}\right)$$=$$\left(\begin{array}{cc}-24&+32 \\ +16&-48\end{array}\right)$$ 

2A-3C^t= \\  \\ C^t=$$\left(\begin{array}{cc}5&7 \\ 1&-2\end{array}\right)$$ \\  \\  \\ 2$$\left(\begin{array}{cc}4&-3 \\ 6&-2\end{array}\right)$$-3$$\left(\begin{array}{cc}5&7 \\ 1&-2\end{array}\right)$$= \\  \\  \\ $$\left(\begin{array}{cc}8&-6 \\ 12&-4\end{array}\right)$$-$$\left(\begin{array}{cc}15&21 \\ 3&-6\end{array}\right)$$= \\  \\  \\ $$\left(\begin{array}{cc}8-15&-6-21 \\ 12-3&-4+6\end{array}\right)$$=$$\left(\begin{array}{cc}-7&-27 \\ 9&2\end{array}\right)$$

lavinnea: Valeu♥ Obrigada!!!
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