Question

Dadas as matrizes A = -4,1 e 3,2 e B = 1,-1 e 0,3, calcule o determinante da matriz 3AxB

Answer 1

A = $\left[\begin{array}{ccc}-4&1&\\3&2&\\\end{array}\right]$
B = $\left[\begin{array}{ccc}1&-1&\\0&3&\\\end{array}\right]$

3A = $\left[\begin{array}{ccc}-12&3&\\9&6&\\\end{array}\right]$

$\left[\begin{array}{ccc}-12&3&\\9&6&\\\end{array}\right]$ . $\left[\begin{array}{ccc}1&-1&\\0&3&\\\end{array}\right]$ = $\left[\begin{array}{ccc}-12&21&\\9&9&\\\end{array}\right]$

-12.1 + 3.0  = -12 + 0 = -12
-12.-1 + 3.3 = +12 + 9 = 21
9.1 + 6.0 = 9 + 0 = 9
9.-1 + 6.3 = -9 + 18 = 9

Answer 2

Resposta:

-297

Explicação passo-a-passo: