Question

dadas as matrizes A=(2 3 6), B=(1 2 4) c=(0 4 2), calcule:
A) A+B-C
B) A-B+C
C) A-B.C​

Answer 1

a) A+B-C

$\left[\begin{array}{ccc}2\\3\\6\end{array}\right]+\left[\begin{array}{ccc}1\\2\\4\end{array}\right]-\left[\begin{array}{ccc}0\\4\\2\end{array}\right]=\left[\begin{array}{ccc}2+1-0\\3+2-4\\6+4-2\end{array}\right]=\left[\begin{array}{ccc}3\\1\\8\end{array}\right]$

b) A-B+C

$\left[\begin{array}{ccc}2\\3\\6\end{array}\right]-\left[\begin{array}{ccc}1\\2\\4\end{array}\right]+\left[\begin{array}{ccc}0\\4\\2\end{array}\right]=\left[\begin{array}{ccc}2-1+0\\3-2+4\\6-4+2\end{array}\right]=\left[\begin{array}{ccc}1\\5\\4\end{array}\right]$

c) A-B.C

$\left[\begin{array}{ccc}2\\3\\6\end{array}\right]-\left[\begin{array}{ccc}1\\2\\4\end{array}\right]*\left[\begin{array}{ccc}0\\4\\2\end{array}\right]=\left[\begin{array}{ccc}2-1\\3-2\\6-4\end{array}\right]*\left[\begin{array}{ccc}0\\4\\2\end{array}\right]=\left[\begin{array}{ccc}1\\1\\2\end{array}\right]*\left[\begin{array}{ccc}0\\4\\2\end{array}\right]$

$=\left[\begin{array}{ccc}1\\1\\2\end{array}\right]*\left[\begin{array}{ccc}0&4&2\end{array}\right]=\left[\begin{array}{ccc}1*0&1*4&1*2\\1*0&1*4&1*2\\2*0&2*4&2*2\end{array}\right]=\left[\begin{array}{ccc}0&4&2\\0&4&2\\0&8&4\end{array}\right]$

Espero ter ajudado!

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