Question

Dadas as matrizes
A=( 2 -3)
4 -1
B=(0 1)
2 3
C= (-2 8)
1 -3
calcule: 6A-3B
2B-C

Answer 1

Resposta:

6A - 3B

$6.\begin{pmatrix}2&-3\\ 4&-1\end{pmatrix}-3.\begin{pmatrix}0&1\\ 2&3\end{pmatrix}=\\ \\ \\ \begin{pmatrix}6.2&6.(-3)\\ 6.4&6.(-1)\end{pmatrix}-\begin{pmatrix}3.0&3.1\\ 3.2&3.3\end{pmatrix}=\\ \\ \\ \begin{pmatrix}12&-18\\ 24&-6\end{pmatrix}-\begin{pmatrix}0&3\\ 6&9\end{pmatrix}=\\ \\ \\ \begin{pmatrix}12-0&18-3\\ 24-6&-6-9\end{pmatrix}=\begin{pmatrix}12&-21\\ 18&-15\end{pmatrix}$

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2B - C

$2.\begin{pmatrix}0&1\\ 2&3\end{pmatrix}-\begin{pmatrix}-2&8\\ 1&-3\end{pmatrix}=\\ \\ \\ \begin{pmatrix}2.0&2.1\\ 2.2&2.3\end{pmatrix}-\begin{pmatrix}-2&8\\ 1&-3\end{pmatrix}=\\ \\ \\ \begin{pmatrix}0&2\\ 4&6\end{pmatrix}-\begin{pmatrix}-2&8\\ 1&-3\end{pmatrix}=\\ \\ \\ \begin{pmatrix}0-(-2)&2-8\\ 4-1&6-(-3)\end{pmatrix}=\begin{pmatrix}2&-6\\ 3&9\end{pmatrix}$