Question

dadas as matrizes A=(2,0,1;3,2,-3) e B=(1,4,0;2,-1,1),o determinante do produto At×b vale.​

Answer 1

Resposta:

2) At=[2,0,1;3,1,-3].B=[1,4,0;2,-1,1]

2.1=2

0.4=0

1.0=0

3.2=6

-3.1=-3

1.(-1)=-1

2.0.0.6.(-3).(-1)=0

resposta letra A

3) A=[ a11 a12 a13; a21 a22 a23;a31 a32 a33]=[1,0,0;0,1,0;0,0,1]

B=[a11,a12,a13;a21,a22 a23;a31 a32 a33]=[2,0,0;0,2,0;0,0,2]

1.2=2

0.0=0

0.0=0

0.0=0

1.2=2

0.0=0

0.0=0

0.0=0

1.2=2

2.2.2=8

resposta letra E

4) [a11,a12,a13;a21,a22 a23;a31 a32 a33]

A11=2.1-1=2-1=1

A12=2.1-1=2-2=0

A13=2.1-3=2-3=-1

A21=2.2-1=4-1=3

A22=2.2-2=4-2=2

A23=2.2-3=4-3=1

A31=2.3-1=6-1=5

A32=2.3-2=6-2=4

A33=2.3-3=6-3=3

A=[1,0,-1;3,2,1;5,4,3]

DP=1.2.3+0.1.5+(-1)3.4=6+0-12=-6

DS=(-1).2.5+1.1.4+0.3.3=-10+4=-6

-6-(-6) OU +6+6=0

ESPERO DE AJUDADO!