Question

dadas as funções f(x)=x²+1 e g (x)= 3x -1, calcule f(f(x)) e g(g(x)).

Answer 1

Vamos lá .

f(f(x)) = f(x²+1)

f(f(x)) = (x²+1)² + 1

f(f(x)) = x⁴+2x²+1+1

f(f(x)) = x⁴+2x²+2

Agora g(g(x)) :

g(g(x)) = g(3x-1)

g(g(x)) = 3.(3x-1) - 1

g(g(x)) = 9x-3 - 1

g(g(x)) = 9x-4

Answer 2

Boa tarde!

I.

f(f(x)) = (x² + 1)² + 1
f(f(x)) = (x²+1).(x²+1) + 1
f(f(x)) = x^4 + x^2 + x^2 + 1 + 1
f(f(x)) = x^4 + 2x^2 + 2


II.

g(g(x)) = 3.(3x-1) - 1
g(g(x)) = 9x - 3 - 1
g(g(x)) = 9x - 4



Espero ter ajudado!