Question

dadas as funcoes f(x) =x +7 e g (x)=x^2 -3x+10 calcule gof (x)

Answer 1

$\left\{ \!\begin{array}{l} f(x)=x+7\\\\ g(x)=x^2-3x+10 \end{array} \right.$


Se $g(x)=x^2-3x+10,$ então

$g\circ f(x)=g(f(x))\\\\ g\circ f(x)=(f(x))^2-3\,f(x)+10\\\\ g\circ f(x)=(x+7)^2-3\,(x+7)+10\\\\ g\circ f(x)=x^2+14x+49-3x-21+10\\\\ g\circ f(x)=x^2+14x-3x+49-21+10\\\\ \boxed{\begin{array}{c}g\circ f(x)=x^2+11x+38 \end{array}}$