Question

Dadas as funções f(x) = x + 4 e g(x) = 2x - 1, o valor da soma de f(9) + g(2) é:

Answer 1

Para calcular qualquer função que seja, basta alterarmos o valor dado pela incógnita x na função geral.

$\large\begin{array}{lr}\sf f(x)= x+4\left\{\begin{array}{ll}\sf x\rightarrow 9\end{array}\right.\end{array}$

$\large\begin{array}{lr}\sf g(x)= 2x-1\left\{\begin{array}{ll}\sf x\rightarrow 2\end{array}\right.\end{array}$

Vamos primeiro calcular o f(9).

$\large\begin{array}{lr}\sf f(x)= x+4\\\\\sf f(9)= 9+4\\\\\sf f(9) = \underline{\boxed{\red{\sf 13}}}\end{array}$

Agora iremos calcular o g(2).

$\large\begin{array}{lr} \sf g(x)= 2x-1\\\\\sf g(2) = 2(2) -1\\\\\sf g(2) = 4-1\\\\\sf g(2) = \underline{\boxed{\red{\sf 3}}} \end{array}$

A questão pede o valor da soma entre f(9) e g(2), então:

$\large\begin{array}{lr} \sf f(9)+g(2)\\\\\sf 13 + 3\\\\\sf = \underline{\boxed{\red{\sf 16}}} \end{array}$

Espero ter ajudado.

Bons estudos.

• Att. FireClassis.

Answer 2

$\Huge \sf f(x) = x + 4 \dfrac {} {}\\\Huge \sf f(9) = 9 + 4 \dfrac {} {}\\\Huge \sf f(9) = 13 \dfrac {} {}$

$\Huge \sf g(x) = 2x - 1 \dfrac {} {}\\\Huge \sf g(2) = 2.2-1 \dfrac {} {}\\\Huge \sf g(2) = 4 - 1 \dfrac {} {}\\\Huge \sf g(2) = 3 \dfrac {} {}$

$\Huge \sf f(9) + g(2) \dfrac {} {}\\\Huge \sf 13 + 3 \dfrac {} {}\\\Huge \sf 16 \dfrac {} {}$

$\Longrightarrow \large\text{ O valor da soma de f(9) + g(2) {\'e}: 16}$

$\boxed{\HUGE \sf PERE1RABR \dfrac {} {}\begin{array}{lr} \\\end{array}}$

$\Large{\LaTeX}$