Question

Dadas as funções:

f(x) = 3√(1 - x)

(raiz cúbica de (1 - x))

 

e

 

g(x) = 1 - x3 

 

calcule:

 

a) fog(x)
b) gof(x)

Answer 1

a) f(g(x)) =  raizcubica ( 1- (1-x3) = raiz cúbica( 1-1+x3) =  raiz cúbica x3 = x

 

 

b) 1-(raiz cúbica(1-x))^3 = 1-(1-x)  => 1 - 1 +x => x

 

 

são iguais

 

e fui.

Answer 2

a) f(g(x)) =  raizcubica ( 1- (1-x3) = raiz cúbica( 1-1+x3) =  raiz cúbica x3 = x

 

 

b) 1-(raiz cúbica(1-x))^3 = 1-(1-x)  => 1 - 1 +x => x