dadas as funções f(x)2x2-6x-4 e g(x)=-3×2-5×.
a} f(3)
b} f(-2)
c} f(-0,2)
d} g(-4)
e} g(1/2)
f} g (0)
Soluções para a tarefa
f(3)=2(9) -18 -4
f(3)=18 -18 -4
f(3)= -4
B)f(-2)=2(-2)² -6(-2) -4
f(-2)=2(4)+12 -4
f(-2)=8+12 -4
f(-2)=20 -4
f(-2)=16
C)f(-0,2)=2(-0)² -6(-0) -4
2= -4
f(-0,2)= -4 -2
f(-0,2)= -6
D)g(-4)= -3(-4)² -5(-4)
g(-4)= -3(16)+20
g(-4)= -48+20
g(-4)= -28
E)g(1/2)= -3(1/2)² -5(1/2)
g(1/2)= -3(1/4) -5/2
g(1/2)= -3/4 -5/2 (tira o mmc de 4 e 2, que da 4)
g(1/2)= -13/4
F)g(0)= -3(0)² -5(0)
g(0)= -3(0)
g(0)= 0
Resposta:
a) f(x) = 2x^2 - 6x - 4; f(3) = 2.3^2 - 6.3 - 4; f(3) = 2.9 - 18 - 4; f3) = 18-18-4; f(3) = - 4.
b) f (-2) = 2.(-2)^2 - 6.(-2) - 4; f(-2) = 2.4 + 12 - 4; f(-2) = 8+8; f(-2) = 16.
c) f(0) = 2.0^2 -6.0 - 4; f(0) = 0-0-4; f(0) = - 4.
d) f(-1/2) = 2.(-1/2)^2 - 6.(-1/2) - 4; f(-1/2) = 2. 1/4 -6/2 - 4; f(-1/2) = 2/4 - 3 - 4; f(-1/2) = 1/2 - 7; f(-1/2) = (1-14)/2 ; f(-1/2)= -13/2.
e) g(x) = -3x^2 -5x +1; g(1) = -3.1^2 -5.1 +1; g(1) = -3.1 - 5 + 1; g(1) = -3 - 4; g(1) = - 7.
f) g(-4) = -3.(-4)^2 -5.(-4) + 1; g(-4) = -3.16 +20+1; g(-4) = -48 +21; g(-4) = - 27.
g) g(0) = -3.0^2 -5.0 + 1; g(0) = 1.
h) g(1/2) = -3.(-1/2)^2 -5.1/2 + 1; g(1/2) = -3.1/4 -5/2 + 1; g(1/2) = -3/4 -5/2 + 1; g(1/2) = (-3 - 10 +4)/4; g(1/2) = -9/4.
i) g(2) = -3.2^2 -5.2 + 1; g(2) = -3.4 -10+1; g(2) = -12-9; g(2)
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