Question

Dadas as funções definidas por f(x) = 1/2 x + 1 e g(x) = x2 - 1,
calcule f(6) + g(-2).​

Answer 1

$f(x) = \frac{1}{2}.x + 1\\ g(x) = x^2 - 1\\\\f(6) + g(-2) = (\frac{1}{2}.6 + 1) + ((-2)^2 - 1) = (3 + 1) + (4 - 1) = 4 + 3 = 7$