Question

Dadas a função definida por: f(x)=x²-3x+2, calcule.
A) f(0)
B) f(1)
C) f(-1)
D) f(-5)
E) f(+2)

Answer 1

f(x)=x^2-3x+2
a) f(0)=0^2-3.0+2=0-0+2=2
b) f(1)=1^2-3.1+2=1-3+2=-2+2=0
c) f(-1)=(-1)^2-3.(-1)+2=1+3+2=6
d) f(-5)=(-5)^2-3.(-5)+2=25+15+2=42
e) f(2)=2^2-3.2+2=4-6+2=-2+2=0