Question

Dada log2=0,3010,log3=0,4771 e log 7=0,8460 calcule log 15

Answer 1

sendo_

log(2) = 0.3010

log(3) = 0.4771

log(5) = log(10/2) = log(10) - log(2) = 1 - log(2) = 0.699

log(15) = log(3*5) = log(3) + log(5)

log(15) = 0.4771 + 0.699 = 1.1761