Question

Dada f(x)=2x-1/3x x édiferente de 0 determine f-¹(x+1)

Answer 1

$f(x)=\frac{2x-1}{3x}\\\\y=\frac{2x-1}{3x}\\\\x=\frac{2y-1}{3y}\\\\3y.x=2y-1\\\\3y.x-2y=-1\\\\y(3x-2)=-1\\\\y=\frac{-1}{3x-2}\\\\f^{-1}(x)=\frac{-1}{3x-2}\\\\f^{-1}(x+1)=\frac{-1}{3(x+1)-2}\\\\f^{-1}(x+1)=\frac{-1}{3x+1}$