Question

dada da função (fx) = X2-3X- 10 calcule f(1/2)

Answer 1

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Answer 2

$f(x) = x^2-3x- 10 \\\\f(\frac{1}{2}) = (\frac{1}{2})^2-3*(\frac{1}{2})- 10\\\\f(\frac{1}{2}) = \dfrac{1}{4}-\dfrac{3}{2}- 10\\\\f(\frac{1}{2}) = \dfrac{1-6-40}{4} = \dfrac{-45}{4} = -11.25$