Dada as matrizes A= ![\left[\begin{array}{ccc}2&x\\3&9\end{array}\right]](https://tex.z-dn.net/?f=++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26amp%3Bx%5C%5C3%26amp%3B9%5Cend%7Barray%7D%5Cright%5D+ "\left[\begin{array}{ccc}2&x\\3&9\end{array}\right]")
B= ![\left[\begin{array}{ccc}-1&-1&0\\2&3&x\\-1 &2&1\end{array}\right]](https://tex.z-dn.net/?f=++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26amp%3B-1%26amp%3B0%5C%5C2%26amp%3B3%26amp%3Bx%5C%5C-1++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++%26amp%3B2%26amp%3B1%5Cend%7Barray%7D%5Cright%5D+ "\left[\begin{array}{ccc}-1&-1&0\\2&3&x\\-1 &2&1\end{array}\right]")
, determine x para que det A = det B
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ΔA = (2.9) - (3.x) = 18 - 3x
ΔB = [(-1.3.1)+(2.2.0)+(-1.x.-1)] - [(-1.3.0)+(2.-1.1)+(2.x.-1)]
ΔB = [(-3+0+x) - (0-2-2x)]
ΔB = (x-2x-3-2)
ΔB = -x-5
ΔA = ΔB --> 18-3x = -x-5
-3x+x = -5-18
-2x = -23 .(-1)
2x = 23
x = 23/2
ΔB = [(-1.3.1)+(2.2.0)+(-1.x.-1)] - [(-1.3.0)+(2.-1.1)+(2.x.-1)]
ΔB = [(-3+0+x) - (0-2-2x)]
ΔB = (x-2x-3-2)
ΔB = -x-5
ΔA = ΔB --> 18-3x = -x-5
-3x+x = -5-18
-2x = -23 .(-1)
2x = 23
x = 23/2
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