Question

Dada as funções f(x) = x+1, g(x) = 2x – 3 e h(x) = 3x + 2, calcule f(f(-2)) + g(g(1)) - f(h(0))

Answer 1

F(x)= x+1

G(X)= 2x-3

H(x)= 3x+2

F(-2)= -2+1 F(-1)= -1+1

F(-2)= -1 F(-1)= 0

G(1)= 2.1-3 G(-1)= 2(-1)-3

G(1)= 2-3 G(-1)= -2-3

G(1)= -1 G(-1)= -5

H(0)= 3.0+2 F(2)= 2+1

H(0)= 0+2 F(2)= 3

H(0)= 2

f(f-2))+g(g(1))-f(h0)))

0+(-5)-(+2)

0-5-2

-7