Dada as funções f : A⇒R onde A= {1;2;3} e f(x)=2x-1/2
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Olá!!!
Resoluçao!!!
f ( x ) = 2x - 1/2
A = { 1, 2, 3, }
• f ( 1 )
f ( x ) = 2x - 1/2
f ( 1 ) = 2 • ( 1 ) - 1/2
f ( 1 ) = 2 - 1/2
f ( 1 ) = ( 4 - 1 )/2
f ( 1 ) = 3/2
• f ( 2 )
f ( x ) = 2x - 1/2
f ( 2 ) = 2 • ( 2 ) - 1/2
f ( 2 ) = 4 - 1/2
f ( 2 ) = ( 8 - 1 )/2
f ( 2 ) = 7/2
• f ( 3 )
f ( x ) = 2x - 1/2
f ( 3 )= 2 • ( 3 ) - 1/2
f ( 3 ) = 6 - 1/2
f ( 3 ) = ( 12 - 1 )/2
f ( 3 ) = 11/2
A = { 1......, 2 , ..,3 }
.........↓........↓......↓.......
B = { 3/2, 7/2, 11/2, }
Espero ter ajudado!!
Resoluçao!!!
f ( x ) = 2x - 1/2
A = { 1, 2, 3, }
• f ( 1 )
f ( x ) = 2x - 1/2
f ( 1 ) = 2 • ( 1 ) - 1/2
f ( 1 ) = 2 - 1/2
f ( 1 ) = ( 4 - 1 )/2
f ( 1 ) = 3/2
• f ( 2 )
f ( x ) = 2x - 1/2
f ( 2 ) = 2 • ( 2 ) - 1/2
f ( 2 ) = 4 - 1/2
f ( 2 ) = ( 8 - 1 )/2
f ( 2 ) = 7/2
• f ( 3 )
f ( x ) = 2x - 1/2
f ( 3 )= 2 • ( 3 ) - 1/2
f ( 3 ) = 6 - 1/2
f ( 3 ) = ( 12 - 1 )/2
f ( 3 ) = 11/2
A = { 1......, 2 , ..,3 }
.........↓........↓......↓.......
B = { 3/2, 7/2, 11/2, }
Espero ter ajudado!!
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