Question

Dada a taxa de 0,95% ao mes, calcule a taxa equivalente de juros compostos em 1 período de 1 ano, 5 meses e 11 dias

Answer 1

$(1 \ + \ i)^3^0 \ = \ (1 \ + \ 0,0095)^5^2^1 \\ \\ (1 \ + \ i)^3^0 \ = \ (1,0095)^5^2^1 \\ \\ (1 \ + \ i)^3^0 \ = \ 137,8460826 \\ \\ 1 \ + i \ = \ \sqrt[30]{137,8460826} \\ \\ 1 \ + \ i \ = \ 1,178455391 \\ \\ i \ = \ 1,178455391 \ - \ 1$

$i \ = \ 0,178455391 \\ \\ i \ = \ 17,84553914 \ \% \\ \\ i \ = \ 17,85\%$