Question

Dada a reação não-balanceada : Zn+HCl ->ZnCl2+H2
Qual o numero de atomos de zinco que reagem completamente com 5 mols de acido cloridrico(HCl) ?

Answer 1

$Ola'~~~\mathbb{AMANDA} \\ \\ Sendo~a~reac\~ao: \\ \\ Zn+HCl=\ \textgreater \ ZnCl_2+H_2~~~--\ \textgreater \ balanceando~temos: \\ \\ \mathbf{1}Z_n+\mathbf{2}ZnCl=\ \textgreater \ \mathbf{1}ZnCl_2+\mathbf{1}H_2~~--\ \textgreater \ equac\~ao~balanceada \\ \\ Temos~em: \\ \\ 1mol~Zn----\ \textgreater \ 2mol~ZnCl \\ ~~~~x------\ \textgreater \ 5mol~ZnCl \\ \\ Por~regra~de~3~temos:$

$x= \frac{5(1mol~Zn)}{2} \\ \\ x=2,5mol~Zn~~--\ \textgreater \ se~sabe~que~\boxed{1mol=6,02.10 ^{23}\^atomos } \\ \\ x=2,5.(6,02. 10^{23}\^atomos ~de~Zn)~~--\ \textgreater \ multiplicamos \\ \\ x=15,05.10 ^{23}\^atomos~de~Zn \\ \\ \boxed{\boxed{x=1,51.10 ^{24}\^atomos~de~Zn} } \\ \\ \mathbb{aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa}\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Espero~ter~ajudado!!$