Question

dada a pg (2,4...1024) determine o número de termos .. preciso dos cálculos pfv

Answer 1

a1. qⁿ-¹ = an.........onde:
qⁿ-¹ = an/a1
2ⁿ-¹ = 1024/2
2ⁿ-¹ = 512
2ⁿ-1 = 2^9
n-1 = 9
n = 10 ✓

Answer 2

Resposta:

São 10 termos

Explicação passo-a-passo:

$a_n=1024\\ a_1=2\\ r=q=4\div2=2\\ n=?\\ \\ termo~~geral\\ \\ a_n=a_1.q^{n-1}\\ \\ 1024=2.2^{n-1}\\ \\ 1024\div2=2^{n-1}\\ \\ 512=2^{n-1}\\ \\ fatorar~~512\\ \\ 2^9=2^{n-1}\\ \\ Exponencial~~~cancela~~a base~~(2)\\ \\ n-1=9\\ \\ n=9+1\\ \\ n=10 \mapsto~~termos$