Question

Dada a PG (1,2,4,8...) calcule o decimo termo dessa progressão geométrica

Answer 1

Explicação passo-a-passo:

lembrando do termo da PG an= a1·q^n – 1

a10= 1. 2^9= 512

Answer 2

$> \: resolucao \\ \\ \geqslant \: progressao \: \: geometrica \\ \\ q = \frac{a2}{a1} = \frac{2}{1} = 2 \\ \\ = = = = = = = = = = = = = = = = = \\ \\ > \: o \: decimo \: termo \: da \: pg \\ \\ an = a1 \times q {}^{n - 1} \\ an = 1 \times 2 {}^{10 - 1} \\ an = 1 \times 2 {}^{9} \\ an = 1 \times 512 \\ an = 512 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant \geqslant \geqslant$