Question

Dada a PG (1,2...,1024) calcule a soma dos termos.

Answer 1

a1 = 1
a2 =  2
an = 1024
q = 2/1 = 2 ****
1024 = 1.2^n-1
2^10  = 2^n-1
n - 1 = 10
n = 10 + 1
n = 11 ***

S11 =  1 [ 2^11)  - 1  ]/ ( 2 - 1)
S11 = 20248 - 1
S11 = 20247 ****