Dada a PA (1,7,13,...), calcule:
a) o 40° termo.
b) a soma dos 40 primeiros termos.
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a)an=a1+(n-1).r
a40=1+(40-1).6
a40=1+39.6
a40=235
b=)Sn=![\frac{(a1+an).n}{2} \frac{(a1+an).n}{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B%28a1%2Ban%29.n%7D%7B2%7D+)
S40=![\frac{(1+235).40}{2} \frac{(1+235).40}{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B%281%2B235%29.40%7D%7B2%7D+)
S40=![\frac{9440}{2} \frac{9440}{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B9440%7D%7B2%7D+)
S40=4720
a40=1+(40-1).6
a40=1+39.6
a40=235
b=)Sn=
S40=
S40=
S40=4720
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