Matemática, perguntado por sorayaantonela2005, 10 meses atrás

dada a p.a (4,10,16,22)determine
a)a razão
b)o 20 termo
c)a soma dos 40 primeiros termos​

Soluções para a tarefa

Respondido por jenifferolivei48
1

(4,10,16,22,28,34,40,46,52,58,64,70,76,82,88,94,100,106,112,118)

A)6

B)118

C)238

4,10,16,22,28,34,40,46,52,58,64,70,76,82,88,94,100,106,112,118,124,130,136,142,148,154,160,166,172,178,184,190,196,202,208,214,220,226,232,238

4+6=10+6=16+6=22+6=28+6=34+6=40+6=46+6=52+6=58+6=64+6=70+6=76+6=82+6=88+6=94+6=100+6=106+6=112+6=118+6=124+6=130+6=136+6=142+6=148+6=154+6=160+6=166+6=172+6=178+6=184+6=190+6=196+6=202+6=208+6=214+6=220+6=226+6=232+6=238

Espero ter ajudado!

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