Dada a matriz abaixo determine 3A+2A
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primeiro calculamos 2A
![2. \left[\begin{array}{ccc}6&3&-2\\-5&2&8\\\end{array}\right] = \left[\begin{array}{ccc}12&6&-4\\-10&4&16\\\end{array}\right] 2. \left[\begin{array}{ccc}6&3&-2\\-5&2&8\\\end{array}\right] = \left[\begin{array}{ccc}12&6&-4\\-10&4&16\\\end{array}\right]](https://tex.z-dn.net/?f=2.++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26amp%3B3%26amp%3B-2%5C%5C-5%26amp%3B2%26amp%3B8%5C%5C%5Cend%7Barray%7D%5Cright%5D+%3D+++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%26amp%3B6%26amp%3B-4%5C%5C-10%26amp%3B4%26amp%3B16%5C%5C%5Cend%7Barray%7D%5Cright%5D+)
agora calculamos 3A
![3. \left[\begin{array}{ccc}6&3&-2\\-5&2&8\\\end{array}\right] = \left[\begin{array}{ccc}18&9&-6\\-15&6&24\\\end{array}\right] 3. \left[\begin{array}{ccc}6&3&-2\\-5&2&8\\\end{array}\right] = \left[\begin{array}{ccc}18&9&-6\\-15&6&24\\\end{array}\right]](https://tex.z-dn.net/?f=3.++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26amp%3B3%26amp%3B-2%5C%5C-5%26amp%3B2%26amp%3B8%5C%5C%5Cend%7Barray%7D%5Cright%5D+%3D+++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D18%26amp%3B9%26amp%3B-6%5C%5C-15%26amp%3B6%26amp%3B24%5C%5C%5Cend%7Barray%7D%5Cright%5D+)
por fim , é só somar as matrizes obtidas acima
![\left[\begin{array}{ccc}12&6&-4\\-10&4&16\\\end{array}\right] + \left[\begin{array}{ccc}18&9&-6\\-15&6&24\\\end{array}\right] = \boxed{ \left[\begin{array}{ccc}30&15&-10\\-25&10&40\\\end{array}\right] } \left[\begin{array}{ccc}12&6&-4\\-10&4&16\\\end{array}\right] + \left[\begin{array}{ccc}18&9&-6\\-15&6&24\\\end{array}\right] = \boxed{ \left[\begin{array}{ccc}30&15&-10\\-25&10&40\\\end{array}\right] }](https://tex.z-dn.net/?f=++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%26amp%3B6%26amp%3B-4%5C%5C-10%26amp%3B4%26amp%3B16%5C%5C%5Cend%7Barray%7D%5Cright%5D+%2B+++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D18%26amp%3B9%26amp%3B-6%5C%5C-15%26amp%3B6%26amp%3B24%5C%5C%5Cend%7Barray%7D%5Cright%5D+%3D++%5Cboxed%7B+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D30%26amp%3B15%26amp%3B-10%5C%5C-25%26amp%3B10%26amp%3B40%5C%5C%5Cend%7Barray%7D%5Cright%5D+%7D)
agora calculamos 3A
por fim , é só somar as matrizes obtidas acima
beatrizmoroni:
Me ajudou muito ! Obrigada :)
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