Question

dada a integral trigonometrica superior pi/3 e inferior pi/6 dteta/sen2 teta

Answer 1

Boa noite Rayssa

I(t) = ∫ 1/sen²(t) dt = -cot(t) + C

I(pi/3) = -cot(pi/3) = -√3/3

I(pi/6) = -cot(pi/6) = -√3

I(pi/3) - I(pi/6) = -√3/3 + 3√3/3 = 2√3/3

.