Matemática, perguntado por alanarodriguesd, 1 ano atrás

Dada a igualdade (6x+4)+ (2x+6)i=(4y+3x)-4yi determine o valor de x e y

Soluções para a tarefa

Respondido por madelaidefesta
0

  (6x+4)+ (2x+6)i=(4y+3x)-4yi 

 6x + 4 = 4y + 3x       /      2x + 6 = - 4y

6x -3x = 4y -- 4          /     2 [4/3 (y - 1)] + 6 = - 4y

3x = 4y - 4                 /     8/3(y - 1) + 6 = - 4y

x = 4/3 (y - 1)            /      8/3 y - 8/3 + 6 = - 4y

                                 /      8/3 y  +   4y      = - 6 + 8/3  -->  mmc = 3

                                        8/3 y   +  12/3 y  =  -18 /3 + 8/3

                                           20/3   y    =    -10/3

                                              20 y  = - 10

                                                  y = -10/20

                                                  y = -1/2

x = 4/3 (y - 1) =

x = 4/3 (-1/2  -   1 )

x = 4/3 (-1/2 - 2/2)

x = 4/3. (-3/2)

x = -12/6 ==> -2

x = -2



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