Question

Dada a funçãof:R → Rdefinida por f(x) = 1/2 x -2/3
determine o valor de f(1/2)+ f (-2/3)

Answer 1

f(x)=1/2x-2/3

f(1/2)=1/2.(1/2)-2/3

f(1/2)=1/4-2/3

f(1/2)=3.1-2.4/4.3

f(1/2)=3-8/12

f(1/2)=-5/12

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f(x)=1/2x-2/3

f (-2/3)=1/2.(-2/3)-2/3

f(-2/3)=-2/6-2/3

f(-2/3)=3.(-2)-2.6/3.6

f(-2/3)=-6-12/18

f(-2/3)=-18/18

f(-2/3)=-1

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f(1/2)+ f (-2/3)=-5/12-1

f(1/2)+ f (-2/3)=-5-1.(12)/12

f(1/2)+f(-2/3)=-5-12/12

f(1/2)+f(-2/3)=-17/12

espero ter ajudado!

boa tarde !

Answer 2

Resposta:

= - 17/12

Explicação passo-a-passo:

f(x) = x/2 - 2/3

f(1/2) = 1/2 : 2 - 2/3

f(1/2) = 1/2 . 1/2 - 2/3

f(1/2) = 1/4 - 2/3

f(1/2) = (3 - 4.2)/12

f(1/2) = (3 - 8)/12

f(1/2) = - 5/12

f(x) = x/2 - 2/3

f(-2/3) = - 2/3 : 2 - 2/3

f(-2/3) = -2/3 . 1/2 - 2/3

f(-2/3) = - 2/6 (:2)/(:2) - 2/3

f(-2/3) = - 1/3 - 2/3

f(-2/3) = - 3/3

f(-2/3) = - 1

= f(1/2) + f(- 2/3)

= - 5/12 + (-1)

= - 5/12 - 1

= ( - 5 - 12)/12

= - 17/12