Question

Dada a função Y=x²+4x-3, determine os valores de f(-2), f(-1), f(0), f(1), f(2)

Answer 1

f(-2)
f(-2)=4-8-3 -> f(-2)=-7

f(-1)
f(-1)=1+4-3 -> f(-1)=1

f(0)
f(0)=0+0-4 -> f(0)=-4

f(1)
f(1)=1+4-3 -> f(1)=2

f(2)
f(2)=4+8-3 -> f(2)=9

Answer 2

Y=x²+4x-3
f(-2)= (-2)²+4(-2)-3
f(-2)= 4-8-3
f(-2)=-7



Y=x²+4x-3
f(-1)= (-1)²+4(-1)-3
f(-1)=1-4-3
f(-1)=-6




Y=x²+4x-3
f(0)= (0)²+ 4(0)-3
f(0)=0+0-3
f(0)=-3


Y=x²+4x-3
f(1)=(1)²+4(1)-3
f(1)=1+4-3
f(1)=2


Y=x²+4x-3
f(2)= (2)²+4(2)-3
f(2)=4+8-3
f(2)=9