Question

Dada a função y=-x^2+ x +6 ,determine as raizes.

obs: ^ = elevado

Answer 1

y = -x² + x + 6

Δ = (1)² - 4(-1)(6)
Δ = 1 + 24 = 25
√Δ = √25 = 5

x' = (-1 + 5)/2(-1) = 4/-2 = -2

x'' = (-1 - 5)/2.(-1) = -6/-2 = 3

Resposta: x = -2 ou x = 3

Espero ter ajudado.

Answer 2

Devemos resolver y = - x² + x + 6 com a fórmula de Bhaskara:

$\mathsf{\displaystyle x = \frac {- b \pm \sqrt{\Delta}} { 2a } }$

Aonde Δ = 1² - 4.(-1).(6) = 1 + 24 = 25

$\mathsf{\displaystyle x = \frac {- 1 \pm \sqrt{25}} { 2.(-1) }}$

$\mathsf{\displaystyle x = \frac {- 1 \pm 5} { -2 }}$

Logo, x' será:

$\mathsf{\displaystyle x' = \frac {- 1 + 5} { -2 }}$

$\mathsf{\displaystyle x' = \frac {4} { -2 }}$

$\mathsf{x' = - 2}$

E x'' será:

$\displaystyle x'' = \frac {- 1 - 5} { -2 }$

$\displaystyle x'' = \frac {- 6} { -2 }$

$x'' = 3$

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