Question

dada a função y= 3×+1 calcule f(2)+f(6)

Answer 1

f (x) = y = 3(x) + 1
f (2) = 3 (2) + 1
f (2) = 6 + 1
f (2) = 7

f (6) = 3 (6) + 1
f (6) = 18 + 1
f (6) = 19

f (2) + f (6) ⇒ 7 + 19 = 26

:)