Dada A Função x²-4x+3 determine F(0)e F(1)
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A resoluçao:
![f(0) = {0}^{2} - 4.0 + 3 \\ f(0) = 3 f(0) = {0}^{2} - 4.0 + 3 \\ f(0) = 3](https://tex.z-dn.net/?f=f%280%29+%3D++%7B0%7D%5E%7B2%7D++-+4.0+%2B+3+%5C%5C+f%280%29+%3D+3)
![f(1) = {1}^{2} - 4.1 + 3 \\ 1 - 4 + 3 \\ - 3 + 3 \\ f(1) = 0 f(1) = {1}^{2} - 4.1 + 3 \\ 1 - 4 + 3 \\ - 3 + 3 \\ f(1) = 0](https://tex.z-dn.net/?f=f%281%29+%3D++%7B1%7D%5E%7B2%7D++-+4.1+%2B+3+%5C%5C+1+-+4+%2B+3+%5C%5C++-+3+%2B+3+%5C%5C+f%281%29+%3D+0+)
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