Question

dada a função V (t)=t2 -3t-1,calcule: A) V (0) B)V (-5) C)V (2/3) D)V (-1)

Answer 1

V( t ) = t² -3t - 1
V( 0) = 0² -3(0) - 1 = 0 -0 -1 = -1
V( -5 ) = (-5)² -3(-5) - 1= 25+15-1 = 39
V( 2/3 ) = (2/3)² -3(2/3)- 1= 4/9 -2-1 = -23/9
V( -1) = (-1)² -3(-1) - 1 = 1+3-1 = 3