Question

Dada a função quadratica f(x)=3x²-4x+1 determine o valor de Y quando x=h+1

Answer 1

F(h+1) = 3(h+1)²  - 4(h+1) + 1
F(h+1) = 3(h² + 2h + 1) -4h +1
F(h+1) = 3h² + 6h + 3 -4h -4 +1
F(h+1) = 3h² + 2h