Question

Dada a função quadrática F(x)= 3x²-4x+1, determine: a) F(1)= b) F(0)= c) F(√2)= d) F(-2)= e) F(-1)= f) F(√3)=

Answer 1

f(x) = 3x² - 4x + 1

a) f(1)

f(1) = 3.(1)² - 4.(1) + 1
f(1) = 3.1 - 4.1 + 1
f(1) = 3 - 4 + 1
f(1) = - 1 + 1
f(1) = 0

b) f(0)

f(0) = 3.(0)² - 4.(0) + 1
f(0) = 0 - 0 + 1
f(0) = 1

c) f(√2)

f(√2) = 3.(√2)² - 4√2 + 1
f(√2) = 3.2 - 4√2 + 1
f(√2) = 6 - 4√2 + 1
f(√2) = 7 - 4√2

d) f(-2)

f(-2) = 3.(-2)² - 4.(-2) + 1
f(-2) = 3.4 + 8 + 1
f(-2) = 12 + 8 + 1
f(-2) = 21

e) f(-1)

f(-1) = 3.(-1)² - 4.(-1) + 1
f(-1) = 3.1 + 4 + 1
f(-1) = 3 + 4 + 1
f(-1) = 8

f) √3

f(√3) = 3.(√3)² - 4√3 + 1
f(√3) = 3.3 - 4√3 + 1
f(√3) = 9 - 4√3 + 1
f(√3) = 10 - 4√3