Question

dada a funçao quadratica definida por f(x)= x2+5+6 determine:

a) f(4) b) f(0) c) f(-1/5) d) f(-1)

Answer 1

f(4)= 4*2+5+6
f(4)= 16+11= 27

f(0)= 0*2+5+6
f(0)= 0+11= 11

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f(-1)= -1*2+ 5+6
f (-1)= 1+11=12